The circuit of the figure below shows a capacitor, two ideal batteries, two resistors, and a switch S. Initially S has been open for a long time. If it is then closed for a long time, what is the change in the charge on the capacitor? Assume C = 15 μF, E1 = 1.0 V, E2 = 4.0 V, R1 = 0.20 Ω, and R2 = 0.60 Ω. μC
Consider the circuit shown in the figure below. The ideal battery provides an emf ε = 7.00 V, and the initially uncharged capacitor has capacitance C = 8.53 μF. The resistors are R1 = 2R, R2 = 4R, and R3 = 7R where R = 15 Ω. The switch is closed at t = 0. (a) How much current passes through the capacitor at t = 0? mA (b) How much current passes through the capacitor at t = ∞? mA (c) How much charge is eventually stored on the capacitor at t = ∞? μC (d) How long does it take for the charge on capacitor to increase to 80% of its eventual charge? μs (e) Suppose that the initially uncharged capacitor was filled with a dielectric with dielectric constant κ before the switch was closed at t = 0. In this case, your answer to part (d) would decrease remain the same increase