For the circuit assume VDD = 3.3 V and RL = 1.5 kΩ. The MOSFETs parameters are: kN′ = 0.6 mA/V2, kP′ = 0.2 mA/V2, VTH = 0.5 V, (W/L)1 = 5/1, (W/L)2 = 8/1, λ = 0. (a) Determine the region of operation of M1 and M2 for Vin = 3.1 V. Justify your answer [10 pts] (b) Find Vout for Vin = 0.3 V [10 pts] (c) Calculate a new value for RL such that Vout = 0.25 V when Vin = 0.3 V [5 pts] (a) M1:VGS = 3.3 V > VT, VDS > Vov Active (saturation) M 2 : VGS = 3.1 V, VDS < Vov Triode(linear) (b) Vo = 0.28 V (c) RL = 0.65 k
For the amplifier in the figure given below, assume VDD = 12 V, VSS = 12 V, RSS = 15 kΩ, RD = 22 kΩ, Kn = 400 μA/V2, and VTN = 0.8 V. What are the differential-mode gain, common-mode gain, CMRR, and differential-mode and common-mode input resistances of the given amplifier? The differential-mode gain Adm = ; (Include a minus sign if necessary.) For a differential output, the common-mode rejection ratio CMRR = ; (Round the final answer to three decimal places.) The differential-mode input resistance Rid =
A resistive load inverter in two logic states is given as follows: Let VTN = 0.6 V. For the circuit shown in the figure, VL = 0.6 V, VH = 2.4 V, VDD = 2.4 V, Kn′ = 100 μA/V2, VDS = 0.5, VTN = 0.6 V and power P = 0.0003 W. Find the new values of R and (W/L)S assuming that the power dissipation remains the same? R = Ω (W/L)S = 1/
The circuit in the block has inputs A, A¯, B, and B¯, and output Vout . A, A¯, B, and B¯, are the inputs and outputs of the circuits shown in the left-hand side. Assume VDD = 5 V. A) Which logic gate (NOT, AND, NAND, OR, NOR, XOR) best describes the function between inputs A and B, and output Vout in the circuit shown in the block above? Select only one logic gate. (6 pts) B) Based on the above MOSFET circuit, if inputs A = 1 and B = 1, what is output Vout? (6 pts)