A silicon atom has valence electrons. 6 2 4 10 0 Read more Read less
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![Let A = [1 -4 -3 -4 4 0 2 4 6] and b = [b1 b2 b3] Show that the equation Ax = b does not have a solution for all possible b, and describe the set of all b for which Ax = b does have a solution. How can it be shown that the equation Ax = b does not have a solution for all possible b? Choose the correct answer below. A. Find a vector b for which the solution to Ax = b is the zero vector. B. Row reduce the matrix A to demonstrate that A does not have a pivot position in every row. C. Find a vector x for which Ax = b is the zero vector.
D. Row reduce the matrix A to demonstrate that A has a pivot position in every row. E. Row reduce the augmented matrix [ A b ] to demonstrate that [ A b ] has a pivot position in every row. Describe the set of all b for which Ax = b does have a solution. Type an expression using b1, b2, and b3 as the variables and 1 as the coefficient of b)](https://www.doubtrix.com/js/ckeditor/filemanager/connectors/php/editor/1700960889-Q7.JPG)
