For the autoionization of water at 25.0∘C, the equilibrium constant is

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For the autoionization of water at 25.0∘C, the equilibrium constant is 1.012×10−14. H2O(l) ⇌ H+(aq) + OH−(aq) What is ΔG0 for the process? Round your answer to 4 significant digits. Note: Reference the Fundamental constants table for additional information.

For the autoionization of water at 25.0∘C, the equilibrium constant is 1.012×10−14. H2O(l) ⇌ H+(aq) + OH−(aq) What is ΔG0 for the process? Round your answer to 4 significant digits. Note: Reference the Fundamental constants table for additional information.

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For the autoionization of water at

{25.0}^{\circ} C

, the equilibrium constant is

1.012 \times 10^{- 14}

.

H_{2} O (l) ⇌ H^{+} (a q) + {O H}^{-} (a q)

What is

Δ G^{0}

for the process? Round your answer to 4 significant digits. Note: Reference the Fundamental constants table for additional information.

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