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H2 (g) + C2H4 (g) → C2H6 (g) BE(C−H) = 413 kJ BE(H−H) = 436 kJ BE(C = C) = 614 kJ BE(C−C) = 348 kJ What is the enthalpy of the reaction using bond energies? Your answer should have three significant figures. Provide your answer below: kJ

H2 (g) + C2H4 (g) → C2H6 (g) BE(C−H) = 413 kJ BE(H−H) = 436 kJ BE(C = C) = 614 kJ BE(C−C) = 348 kJ What is the enthalpy of the reaction using bond energies? Your answer should have three significant figures. Provide your answer below: kJ

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H 2 ( g ) + C 2 H 4 ( g ) → C 2 H 6 ( g ) B E ( C − H ) = 413 k J B E ( H − H ) = 436 k J B E ( C = C ) = 614 k J B E ( C − C ) = 348 k J
What is the enthalpy of the reaction using bond energies?
  • Your answer should have three significant figures.
Provide your answer below:
k J

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