NH3(g) + HCl(g) ⟶ NH4Cl(s) Given the standard enthalpies of formation (below), calculate the enthalpy change for the reaction in kilojoules. NH3(g) ΔHf∘ = −46.1 kJ mol HCl(g) ΔHf∘ = −92.3 kJ mol NH4Cl(s) ΔHf∘ = −314.4 kJ mol Your answer should have three significant figures. Provide your answer below: kJ
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