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The calcium content of urine can be determined by the following procedure: Ca2+ + C2O42− → CaC2O4 ⋅H2O(s) CaC2O4 ⋅H2O(s) + H+ → Ca2+ + C2O42− 5C2O42− + 2MnO4− + 16H+ → 10CO2 + 2Mn2+ + 8H2O How much calcium was originally present in the solution if the last step consumes 5.00 mL of 0.100 M permanganate solution? 0.00125 mol 0.200 mol 0.200 mmol 1.25 mol

The calcium content of urine can be determined by the following procedure: Ca2+ + C2O42− → CaC2O4 ⋅H2O(s) CaC2O4 ⋅H2O(s) + H+ → Ca2+ + C2O42− 5C2O42− + 2MnO4− + 16H+ → 10CO2 + 2Mn2+ + 8H2O How much calcium was originally present in the solution if the last step consumes 5.00 mL of 0.100 M permanganate solution? 0.00125 mol 0.200 mol 0.200 mmol 1.25 mol

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The calcium content of urine can be determined by the following procedure:
C a 2 + + C 2 O 4 2 − → C a C 2 O 4 ⋅ H 2 O ( s ) C a C 2 O 4 ⋅ H 2 O ( s ) + H + → C a 2 + + C 2 O 4 2 − 5 C 2 O 4 2 − + 2 M n O 4 − + 16 H + → 10 C O 2 + 2 M n 2 + + 8 H 2 O
How much calcium was originally present in the solution if the last step consumes 5.00 m L of 0.100 M permanganate solution? 0.00125 m o l 0.200 m o l 0.200 m m o l 1.25 m o l

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