Use the information below to answer the question that follows. N2(g) + 3H2(g) ⟶ 2NH3(g) Bond energy of (N≡N) = 941 kJ Bond energy of (H−H) = 436 kJ Bond energy of (N−H) = 391 kJ What is the enthalpy of the reaction using bond energies, in kilojoules? Round your answer to the nearest whole number. Provide your answer below: kJ
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