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Using the information below, calculate ΔH of NH3(g)+HCl(g)⟶NH4Cl(s). 12 N2(g) + 32 H2(g) ⟶ NH3(g)ΔH = −46.19 kJ/mol 12 H2(g) + 12 Cl2(g) ⟶ HCl(g) ΔH = −92.30 kJ/mol 12 N2(g) + 2 H2(g) + 12 Cl2(g)⟶NH4Cl(s)ΔH = −314.4 kJ/mol Your answer should have four significant figures. Provide your answer below: kJ/mol

Using the information below, calculate ΔH of NH3(g)+HCl(g)⟶NH4Cl(s). 12 N2(g) + 32 H2(g) ⟶ NH3(g)ΔH = −46.19 kJ/mol 12 H2(g) + 12 Cl2(g) ⟶ HCl(g) ΔH = −92.30 kJ/mol 12 N2(g) + 2 H2(g) + 12 Cl2(g)⟶NH4Cl(s)ΔH = −314.4 kJ/mol Your answer should have four significant figures. Provide your answer below: kJ/mol

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Using the information below, calculate Δ H of N H 3 ( g ) + H C l ( g ) ⟶ N H 4 C l ( s ) .
1 2 N 2 ( g ) + 3 2 H 2 ( g ) ⟶ N H 3 ( g ) Δ H = − 46.19 k J / m o l 1 2 H 2 ( g ) + 1 2 C l 2 ( g ) ⟶ H C l ( g ) Δ H = − 92.30 k J / m o l 1 2 N 2 ( g ) + 2 H 2 ( g ) + 1 2 C l 2 ( g ) ⟶ N H 4 C l ( s ) Δ H = − 314.4 k J / m o l
  • Your answer should have four significant figures.
Provide your answer below: ◻ k J / m o l

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