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(15 pts) The circuit of Fig. 7 is with VDD = 5 V, VSS = −5 V, IREF = 25 μA, μnCox = 250 μA/V2, μpCox = 160 μA/V2, and Vtn = |Vtp| = 1 V. (a) (10 pts) Find ID1, ID2, ID3, ID4, ID5 for 0.2(W/L)1 = 0.5(W/L)2 = (W/L)3 = (W/L)4 = (W/L)5 = 5. (b) (5 pts) Find the value of R. Figure 7.

(15 pts) The circuit of Fig. 7 is with VDD = 5 V, VSS = −5 V, IREF = 25 μA, μnCox = 250 μA/V2, μpCox = 160 μA/V2, and Vtn = |Vtp| = 1 V. (a) (10 pts) Find ID1, ID2, ID3, ID4, ID5 for 0.2(W/L)1 = 0.5(W/L)2 = (W/L)3 = (W/L)4 = (W/L)5 = 5. (b) (5 pts) Find the value of R. Figure 7.

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  1. (15 pts) The circuit of Fig. 7 is with V D D = 5 V , V S S = − 5 V , I R E F = 25 μ A , μ n C o x = 250 μ A / V 2 , μ p C o x = 160 μ A / V 2 , and V t n = | V t p | = 1 V . (a) (10 pts) Find I D 1 , I D 2 , I D 3 , I D 4 , I D 5 for 0.2 ( W / L ) 1 = 0.5 ( W / L ) 2 = ( W / L ) 3 = ( W / L ) 4 = ( W / L ) 5 = 5 . (b) ( 5 pts) Find the value of R . Figure 7.

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D 8.7 The current-steering circuit of Fig. P8.7 is fabricated in a CMOS technology for which μnCox = 400 μA/V2, μpCox = 100 μA/V2, Vtn = 0.5 V, Vtp = −0.5 V, VAn′ = 6 V/μm, and |VAp′| = 6 V/μm. If all devices have L = 0.5 μm, design the circuit so that IREF = 20 μA, I2 = 80 μA, I3 = I4 = 50 μA, and I5 = 100 μA. Use the minimum possible device widths needed to operate the current source Q2 with voltages at its drain as high as + 0.8 V and to operate the current sink Q5 with voltages at its drain as low as −0.8 V. Specify the widths of all devices and the value of R. Find the output resistance of the current source Q2 and the output resistance of the current sink Q5.

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24. In Fig. 7, VDD = 3 V, (W/L)1 = (20μm/0.2μm), (W/L)2 = (W/L)3 = (W/L)4 = (10μm/0.2μm), R1 = R2 = R3 = 100 kΩ. C1 and C2 are very large, and VB1 = 2 V, VB2 = 1 V. λn = λp = 0.01/V (a) Express the small signal gain of this amplifier using the small signal parameters of MOSFETs (gm, ro) and the resistance of resistors (R1, R2, R3). (10) (b) Ignoring the channel length modulation, determine Vin so that Vx = 2.5 V. (10) (c) Determine the small signal gain of the amplifier at the value of Vin obtained in (b).(10) Figure 7 μnCox = 100 μA/V2, μpCox = 40 μA/V2, Vthn = |Vthp | = 0.5 V, λn = λp = 0
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VDD = 5 V, Vtn = 0.7 V, μnCox = 75 μA/V2, Vtp = −0.7 V, μpCox = 30 μA/V2, (W/L)1 = (W/L)3 = 3, (W/L)2 = (W/L)4 = 6, (W/L)5 = (W/L)6 = (W/L)7 = (W/L)8 is given for the circuit shown below. a) Give the truth table of the circuit shown below. Explain how the circuit works. b) Calculate the minimum value of (W/L) s so that the switching of the Q′ output from "1" to " 0 " occurs at 2.6 V. Explain your solution. c) Explain how you find the propagation delay tPHL.

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