5.36 The current flowing through a 10 kΩ resistor is given by a triangular waveform (#4 in Table 5-4) with A = 4 mA and T = 0.2 s. (a) Determine the exact value of the average power consumed by the resistor. (b) Using a truncated Fourier-series representation of the waveform with only the first four terms, obtain an approximate value for the average power consumed by the resistor. (c) What is the percentage of error in the value given in (b)?
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![A full-wave bridge rectifier circuit is shown in Fig. 2(a) with a "floating" signal generator and grounded load resistor, which is the most common configuration of this rectifier. Its output waveform appears in Fig. 2 b. Note that the output frequency is twice the input frequency, but the time period T and angular period 2π on the horizontal axis refer to the input waveform. Following a similar development to the halfwave rectifier, the dc output voltage from the full-wave bridge rectifier is given by: Vavg = 1π∫θ1 θ2[Vmsin(θ) − 2Vd]dθ Where, the integration is over half the original waveform's period and the 2Vd term is due to the load current flowing through two diodes. The peak output voltage is vo, peak = Vm − 2Vd. The integration limits are found using Eq. 5 with the angles referred to the original input waveform. θ1 = sin−1(2Vd/Vm) and θ2 = π − θ1 However, the full-wave rectifier's conduction angle must be referred to the output waveform's period, which is half that of the input so φ = 2(θ1−θ2). (a) (b) Fig. 2. (a) Full-wave bridge rectifier circuit and (b) output waveform. Perform the following calculations for the full-wave rectifier in Fig. 2. Put your results in Table 1. a. Determine vo,peak, θ1, and θ2 for the rectifier output waveform of Fig. 2 b. b. Calculate the average (dc) value of vo(t) using Eq. 4 . c. Calculate the conduction angle φ.](https://www.doubtrix.com/uploads/editor/6776072514rhzokOtWGl.png)
