A infinite line of charge has charge density λ = −3.7 μC/m. You correctly use Gauss's law to find the magnitude of the electric field outside the line of charge is E(x) = λ2πε0x. What is V(c)−V(d), where c = 3.7 m and d = 11 m ? Be careful to note the order of the potential difference in question.159479 V −159479 V 87014 V −87014 V 11929 V −11929 V 72464 V −72464 V