A TTL inverter prototype is shown in Figure 8 with the following values: VCC = 3 V, RB = 8 kΩ, and RC = 4 kΩ (12 points) Figure 8 . (a) When Vi = 0.15 V, Q2 is off and Q1 is in saturation with VBEssat = 0.75 V and VCEsat = 0.05 V. Calculate the available currents and the power dissipated in the circuit. (b) When vi = VccQ1 is at reversed active mode with βR = 0.25 and Q2 is in saturation mode with VBEsat = 0.75 V and VCEsat = 0.15 V. Calculate all the available currents and the total power of dissipation.

A TTL inverter prototype is shown in Figure 8 with the following values: VCC = 3 V, RB = 8 kΩ, and RC = 4 kΩ (12 points) Figure 8 . (a) When Vi = 0.15 V, Q2 is off and Q1 is in saturation with VBEssat = 0.75 V and VCEsat = 0.05 V. Calculate the available currents and the power dissipated in the circuit. (b) When vi = VccQ1 is at reversed active mode with βR = 0.25 and Q2 is in saturation mode with VBEsat = 0.75 V and VCEsat = 0.15 V. Calculate all the available currents and the total power of dissipation.

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  1. A TTL inverter prototype is shown in Figure 8 with the following values:
V CC = 3 V , R B = 8 k Ω , and R C = 4 k Ω
(12 points)
Figure 8 . (a) When V i = 0.15 V , Q 2 is off and Q 1 is in saturation with V B E s s a t = 0.75 V and V CEsat = 0.05 V . Calculate the available currents and the power dissipated in the circuit. (b) When v i = V c c Q 1 is at reversed active mode with β R = 0.25 and Q 2 is in saturation mode with V B E s a t = 0.75 V and V CEsat = 0.15 V . Calculate all the available currents and the total power of dissipation.

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