An infinite sheet of charge has charge density σ = +0.7 μC/m2. You cor

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An infinite sheet of charge has charge density σ = +0.7 μC/m2. You correctly use Gauss's law to find the magnitude of the electric field outside the line of charge is E(x) = σ2 ε0. Which integral below will correctly calculate the potential difference V(x = 7 m)−V(x = 12 m) ? −∫012σ2 ε0 dx −∫∞7σ2 ε0 dx −∫127σ2 ε0 dx −∫07σ2 ε0 dx −∫∞12σ2 ε0 dx −∫127σ2 ε0⋅xdx

An infinite sheet of charge has charge density σ = +0.7 μC/m2. You correctly use Gauss's law to find the magnitude of the electric field outside the line of charge is E(x) = σ2 ε0. Which integral below will correctly calculate the potential difference V(x = 7 m)−V(x = 12 m) ? −∫012σ2 ε0 dx −∫∞7σ2 ε0 dx −∫127σ2 ε0 dx −∫07σ2 ε0 dx −∫∞12σ2 ε0 dx −∫127σ2 ε0⋅xdx

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An infinite sheet of charge has charge density

σ = + 0.7 μ C / m^{2}

. You correctly use Gauss's law to find the magnitude of the electric field outside the line of charge is

E (x) = \frac{σ}{2 ε_{0}}

. Which integral below will correctly calculate the potential difference

V (x = 7 m) - V (x = 12 m)

?

- \int_{0}^{12} \frac{σ}{2 ε_{0}} d x

- \int_{\infty}^{7} \frac{σ}{2 ε_{0}} d x

- \int_{12}^{7} \frac{σ}{2 ε_{0}} d x

- \int_{0}^{7} \frac{σ}{2 ε_{0}} d x

- \int_{\infty}^{12} \frac{σ}{2 ε_{0}} d x

- \int_{12}^{7} \frac{σ}{2 ε_{0}} \cdot x d x

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