For the bridge rectifier circuit shown in the figure below; a. Given the input to be vs = Vssin⁡θ and assuming the minimum conducting angle to be very small (θ0 = 0); use the constant-voltage-drop diode model (VD) to show that: i. The average (or dc component) of the output voltage is Vo≅ (2/π)Vs − 2VD ii. The peak diode current is (Vs − 2VD)/R b. If vs is given to be 15 V (rms) sinusoid, VD = 0.7 V, and R = 150 Ω. Find: i. The numerical values for the quantities defined in part (a) of the question. ii. The PIV (Peak Inverse Voltage) numerical value.

For the bridge rectifier circuit shown in the figure below; a. Given the input to be vs = Vssin⁡θ and assuming the minimum conducting angle to be very small (θ0 = 0); use the constant-voltage-drop diode model (VD) to show that: i. The average (or dc component) of the output voltage is Vo≅ (2/π)Vs − 2VD ii. The peak diode current is (Vs − 2VD)/R b. If vs is given to be 15 V (rms) sinusoid, VD = 0.7 V, and R = 150 Ω. Find: i. The numerical values for the quantities defined in part (a) of the question. ii. The PIV (Peak Inverse Voltage) numerical value.

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For the bridge rectifier circuit shown in the figure below; a. Given the input to be v s = V s sin θ and assuming the minimum conducting angle to be very small ( θ 0 = 0 ) ; use the constant-voltage-drop diode model ( V D ) to show that: i. The average (or dc component) of the output voltage is V o ( 2 / π ) V s 2 V D ii. The peak diode current is ( V s 2 V D ) / R b. If v s is given to be 15 V (rms) sinusoid, V D = 0.7 V , and R = 150 Ω . Find: i. The numerical values for the quantities defined in part (a) of the question. ii. The PIV (Peak Inverse Voltage) numerical value.

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