For the CMOS inverter shown assume Vss = 5 V, Assume VTn = 1 V, Kn = 51.8 μA/V2, VTp = −1.5, Kp = 22.9 μA/V2. At t = 0, the input is switched from low to high logic, then for t > 0, the current Ic (μA) when Vo = 2.7 V is a. -828.80 b. -280.52 c. -741.26 d. -247.55

For the CMOS inverter shown assume Vss = 5 V, Assume VTn = 1 V, Kn = 51.8 μA/V2, VTp = −1.5, Kp = 22.9 μA/V2. At t = 0, the input is switched from low to high logic, then for t > 0, the current Ic (μA) when Vo = 2.7 V is a. -828.80 b. -280.52 c. -741.26 d. -247.55

Image text
For the CMOS inverter shown assume V ss = 5 V , Assume V m n = 1 V , K n = 51.8 μ A N 2 , V i p = 1.5 , K p = 22.9 μ A N 2 . At t = 0 , the input is switched from low to high logic, then for t>0, the current ic ( μ A ) when V 0 = 2.7 V is a. -828.80 b. -280.52 c. -741.26 d. -247.55

Detailed Answer