For the CMOS inverter shown assume Vss = 5 V, Assume VTn = 1 V, Kn = 51.8 μA/V2, VTp = −1.5, Kp = 22.9 μA/V2. At t = 0, the input is switched from low to high logic, then for t > 0, the current Ic (μA) when Vo = 2.7 V is a. -828.80 b. -280.52 c. -741.26 d. -247.55