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For the differential amplifier in the figure, what is iD1 in μA if vG1 = 0.069 V and vG2 = −0.069 V? I = 36 μA, VDD = −VSS = 1.8 V, Vtn = 373 mV, kn′ = 200 μA/V2, and (W/L) = 10. (1 decimal)

For the differential amplifier in the figure, what is iD1 in μA if vG1 = 0.069 V and vG2 = −0.069 V? I = 36 μA, VDD = −VSS = 1.8 V, Vtn = 373 mV, kn′ = 200 μA/V2, and (W/L) = 10. (1 decimal)

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For the differential amplifier in the figure, what is i D 1 in μ A if v G 1 = 0.069 V and v G 2 = − 0.069 V ? I = 36 μ A , V D D = − V S S = 1.8 V , V t n = 373 mV , k n ′ = 200 μ A / V 2 , and ( W / L ) = 10 . (1 decimal)

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