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For the emitter follower of Exercise 12.1 , in which I = 14.8 mA and RL = 1 kΩ, consider the case in which vo is limited to the range −10 V to +10 V. Let Q1 have vBE = 0.6 V at ic = 1 mA, and assume α≃1. Find v1 corresponding to vo = −10 V, 0 V, and +10 V. At each of these points, use small-signal analysis to find the voltage gain vo/vi. Note that the incremental voltage gain gives the slope of the vo-versus- vi characteristic. Ans. −9.36 V, 0.67 V, 10.68 V;0.995 V/V, 0.998 V/V, 0.999 V/V

For the emitter follower of Exercise 12.1 , in which I = 14.8 mA and RL = 1 kΩ, consider the case in which vo is limited to the range −10 V to +10 V. Let Q1 have vBE = 0.6 V at ic = 1 mA, and assume α≃1. Find v1 corresponding to vo = −10 V, 0 V, and +10 V. At each of these points, use small-signal analysis to find the voltage gain vo/vi. Note that the incremental voltage gain gives the slope of the vo-versus- vi characteristic. Ans. −9.36 V, 0.67 V, 10.68 V;0.995 V/V, 0.998 V/V, 0.999 V/V

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For the emitter follower of Exercise 12.1 , in which I = 14.8 m A and R L = 1 k Ω , consider the case in which v o is limited to the range − 10 V to + 10 V . Let Q 1 have v B E = 0.6 V at i c = 1 m A , and assume α ≃ 1 . Find v 1 corresponding to v o = − 10 V , 0 V , and + 10 V . At each of these points, use small-signal analysis to find the voltage gain v o / v i . Note that the incremental voltage gain gives the slope of the v 0 -versus- v l characteristic. Ans. − 9.36 V , 0.67 V , 10.68 V ; 0.995 V / V , 0.998 V / V , 0.999 V / V

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