Question

Notify Me Bookmark

In the circuit below, NMOS is VTH = 0.5 V, μnCox = 10-4 A/V2, W/L = 6/0.2 In the circuit below, PMOS is VTH = -0.5 V, μnCox = 10-4 A/V2, W/L = 6/0.2 Both NMOS and PMOS are λ = 0.1, which means the degree of channel length modulation effect. Vin is 0.005*sin(2000t)[V]. (1) Draw a small signal circuit to find the magnitude of the amplitude of the output signal for the circuit below. (2) Find the magnitude of the amplitude of the output signal for the circuit below.

In the circuit below, NMOS is VTH = 0.5 V, μnCox = 10-4 A/V2, W/L = 6/0.2 In the circuit below, PMOS is VTH = -0.5 V, μnCox = 10-4 A/V2, W/L = 6/0.2 Both NMOS and PMOS are λ = 0.1, which means the degree of channel length modulation effect. Vin is 0.005*sin(2000t)[V]. (1) Draw a small signal circuit to find the magnitude of the amplitude of the output signal for the circuit below. (2) Find the magnitude of the amplitude of the output signal for the circuit below.

Image text
In the circuit below, NMOS is VTH = 0.5 V, μnCox = 10-4 A/V2, W/L = 6/0.2 In the circuit below, PMOS is VTH = -0.5 V, μnCox = 10-4 A/V2, W/L = 6/0.2 Both NMOS and PMOS are λ = 0.1, which means the degree of channel length modulation effect. Vin is 0.005*sin(2000t)[V]. (1) Draw a small signal circuit to find the magnitude of the amplitude of the output signal for the circuit below. (2) Find the magnitude of the amplitude of the output signal for the circuit below.

Detailed Answer

1 0

Please enter your email here. You will get email when this question is answered by our tutor.

Answer
Doubtrix Logo

This Problem has been solved!

You'll get a detailed, step-by-step and expert verified solution.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Login Sign Up
  • Student Reviews:
  • (1)
  • Correct answers (1)
  • Complete solution (1)
  • Step-by-step solution (1)
  • Fully explained (1)

Similar/Related Questions

A differential amplifier circuit is shown in the figure below. In the circuit, VDD = +10 V, the current I provided by the current source is 2 mA and the internal source resistance is RSS = 50 kΩ. The transistor parameters are as follows: - All NMOS: μnCox = 100 μA/ V2, W/L = 10 μm/1.6 μm, Vtn = 0.7V, λnL = 0.10 μm/V - All PMOS: μpCox = 50 μA/V2, W/L = 10μm/1.6μm, Vtp = −0.8 V, λpL = 0.05 μm/V (1) Calculate the DC output voltage VO (ignore the channel length modulation effect of all transistors). (2) Under the differential mode operation (i.e., v1 = 1/2vd, v2 = -1/2vd ), calculate the differential mode small signal voltage gain Ad = vo/vd (include the channel length modulation effect of all transistors). Hint: please pay special attention to the connections of Q3 and Q4 transistors.
Solution
2 0

Assuming that transistors M1 is properly biased ( Vin has a proper DC component and a small-signal component) and M1 and M2 are operating in the saturation region, and capacitor C is large enough such that at the frequency of the input small signal it can be considered as a short circuit, find Find RL such that the magnitude of the small-signal gain of the circuit, namely, ∣Vout/Vin ∣ is 5 V/V. In the following circuit we have: VDD = 3 V (W/L)3 = (W/L)5 = (W/L)6 = 10 (W/L)4 = 40 (W/L)2 = 100 (W/L)1 = 25 R = 1 kΩ The technology parameters are: λ(NMOS) = λ(PMOS) = 0 V−1, γ = 0, VTH(NMOS) = ∣VTH(PMOS)∣ = 0.5 V, μnCox = 0.5 mA/V2, μpCox = 0.25 mA/V2.

Solution
1 0

A current mirror is shown in the figure below. The circuit is designed to mirror an input current of Iin = 0.5 mA. In the circuit, RS = 250 Ω. The two transistors are identical, with the parameters of μnCox = 270 μA/V2, λL = 0.08 μm/V, W/L = 20 μm/0.2 μm, and Vt = 0.5 V. Find: (1) The output current Iout of the circuit (ignore the channel length modulation effect). (2) The minimum output voltage of the current mirror (ignore the channel length modulation effect). (3) The output resistance Rout of the circuit (include the channel length modulation effect). Hint: for part (3), apply the general method of finding the output resistance of a circuit first.
Solution
3 0