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In the circuit of Fig. 4.48, IS1 = IS2 = 3 × 10-16 A. (a) Calculate VB such that IX = 1 mA. (b) With the value of VB found in (a), choose IS3 such that IY = 2.5 mA.

In the circuit of Fig. 4.48, IS1 = IS2 = 3 × 10-16 A. (a) Calculate VB such that IX = 1 mA. (b) With the value of VB found in (a), choose IS3 such that IY = 2.5 mA.

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In the circuit of Fig. 4.48, IS1 = IS2 = 3 × 10-16 A. (a) Calculate VB such that IX = 1 mA. (b) With the value of VB found in (a), choose IS3 such that IY = 2.5 mA.

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