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QUESTION 5: Consider the differential amplifier in Figure P11.17 with parameters V+ = 4 V, V− = −4 V, and IO = 1.3 mA. Neglect base currents and assume VA = ∞ for all transistors. The emitter currents can be written as IE1 = IS1 EXP(VBE1/VT) and IE2 = IS2 EXP(VBE2/VT). If v1 = v2 = 0, IS1 = 3.9×10−15 A and IS2 = 2.4×10−15 A, determine (vO1 − vO2) for RC1 = 7.5 kΩ and RC2 = 7.6 kΩ. IE1 (mA) Format : 0.4062 IE2 (mA) Format: 0.7433 (vO1 − vO2) (V) Format : -8.7625 Figure Pl1.17

QUESTION 5: Consider the differential amplifier in Figure P11.17 with parameters V+ = 4 V, V− = −4 V, and IO = 1.3 mA. Neglect base currents and assume VA = ∞ for all transistors. The emitter currents can be written as IE1 = IS1 EXP(VBE1/VT) and IE2 = IS2 EXP(VBE2/VT). If v1 = v2 = 0, IS1 = 3.9×10−15 A and IS2 = 2.4×10−15 A, determine (vO1 − vO2) for RC1 = 7.5 kΩ and RC2 = 7.6 kΩ. IE1 (mA) Format : 0.4062 IE2 (mA) Format: 0.7433 (vO1 − vO2) (V) Format : -8.7625 Figure Pl1.17

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QUESTION 5: Consider the differential amplifier in Figure P11.17 with parameters V + = 4 V , V − = − 4 V , and I 0 = 1.3 m A .
Neglect base currents and assume V A = ∞ for all transistors. The emitter currents can be written as I E 1 = I S 1 E X P ( V B E 1 / V T ) and I E 2 = I S 2 E X P ( V B E 2 / V T ) . If v 1 = v 2 = 0 , I S 1 = 3.9 × 10 − 15 A and I S 2 = 2.4 × 10 − 15 A , determine ( v O 1 − v O 2 ) for R C 1 = 7.5 k Ω and R C 2 = 7.6 k Ω . I E 1 ( m A ) ◻ Format : 0.4062 I E 2 ( m A ) ◻ Format: 0.7433 ( v O 1 − v O 2 ) ( V ) ◻ Format : -8.7625
Figure Pl1.17

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