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Suppose the common-source stage of the figure below is to provide an output swing from 1 V to 2.5 V. Assume that (W/L) = 100, RD = 2 kΩ, and there are no short channel effects, λ = 0. Knowing that the oxide capacitance is COX = 3.835⋅10−7 F⋅cm−2, the electron mobility μn = 350 cm2⋅V−1⋅s−1 and that the saturation current is given by ID = 12 μn⋅COX⋅WL(VGS − VTH)2, μn = 350 cm2⋅V−1⋅s−1, calculate the input voltages that yield Vout = 1∨ and Vout = 2.5 V. 3.101 V and 5.062 V 0.76 V and 0.81 V 2.333 V and 1.115 V 1.086 V and 0.893 V

Suppose the common-source stage of the figure below is to provide an output swing from 1 V to 2.5 V. Assume that (W/L) = 100, RD = 2 kΩ, and there are no short channel effects, λ = 0. Knowing that the oxide capacitance is COX = 3.835⋅10−7 F⋅cm−2, the electron mobility μn = 350 cm2⋅V−1⋅s−1 and that the saturation current is given by ID = 12 μn⋅COX⋅WL(VGS − VTH)2, μn = 350 cm2⋅V−1⋅s−1, calculate the input voltages that yield Vout = 1∨ and Vout = 2.5 V. 3.101 V and 5.062 V 0.76 V and 0.81 V 2.333 V and 1.115 V 1.086 V and 0.893 V

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Suppose the common-source stage of the figure below is to provide an output swing from 1 V to 2.5 V . Assume that (W/L) = 100 , R D = 2 k Ω , and there are no short channel effects, λ = 0 . Knowing that the oxide capacitance is C O X = 3.835 ⋅ 10 − 7 F ⋅ c m − 2 , the electron mobility μ n = 350 c m 2 ⋅ V − 1 ⋅ s − 1 and that the saturation current is given by I D = 1 2 μ n ⋅ C O X ⋅ W L ( V G S − V T H ) 2 , μ n = 350 c m 2 ⋅ V − 1 ⋅ s − 1 , calculate the input voltages that yield ∨ o u t = 1 ∨ and V out = 2.5 V . 3.101 V and 5.062 V 0.76 V and 0.81 V 2.333 V and 1.115 V 1.086 V and 0.893 V

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Suppose the common-source stage of the figure below is to provide an output swing from 1 V to 2.5 V. Assume that ( W/L) = 100, RD = 2 kΩ, and there are no short channel effects, λ = 0. Knowing that the oxide capacitance is COX = 3.835⋅10−7 F⋅cm−2. the electron mobility μn = 350 cm2⋅V−1⋅s−1 and that the saturation current is given by ID = 12 μn⋅COX⋅W L(VGS − VTH)2, μn = 350 cm2⋅V−1⋅s−1, calculate the input voltages that yield V out = 1 V and V out = 2.5 V.
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