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The circuit shown below includes a device known as op amp. This device has two unusual properties in the circuit shown: (1) Vd = 0 V, and (2) no current can flow into either input terminal (marked "-" and " + " inside the symbol), but it can flow through the output terminal (marked "OUT"). This seemingly impossible situation - in direct conflict with KCL- is a result of power leads to the device that are not included in the symbol. Based on this information, calculate Vout. (HINT: two KVL equations are required, both involving the 5 V source.)

The circuit shown below includes a device known as op amp. This device has two unusual properties in the circuit shown: (1) Vd = 0 V, and (2) no current can flow into either input terminal (marked "-" and " + " inside the symbol), but it can flow through the output terminal (marked "OUT"). This seemingly impossible situation - in direct conflict with KCL- is a result of power leads to the device that are not included in the symbol. Based on this information, calculate Vout. (HINT: two KVL equations are required, both involving the 5 V source.)

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The circuit shown below includes a device known as op amp. This device has two unusual properties in the circuit shown: (1) V d = 0 V , and (2) no current can flow into either input terminal (marked "-" and " + " inside the symbol), but it can flow through the output terminal (marked "OUT"). This seemingly impossible situation - in direct conflict with K C L - is a result of power leads to the device that are not included in the symbol. Based on this information, calculate V out . (HINT: two KVL equations are required, both involving the 5 V source.)

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