The magnitude of the electric field between the two circular parallel plates in the figure is E = (6.0×104) − (5.6×106 t) with E in volts per meter and t in seconds. At t = 0, the field is upward. The plate area is 3.6×10−2 m2. For t > 0, what is the magnitude of the displacement current between the plates?

The magnitude of the electric field between the two circular parallel plates in the figure is E = (6.0×104) − (5.6×106 t) with E in volts per meter and t in seconds. At t = 0, the field is upward. The plate area is 3.6×10−2 m2. For t > 0, what is the magnitude of the displacement current between the plates?

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The magnitude of the electric field between the two circular parallel plates in the figure is
E = ( 6.0 × 10 4 ) ( 5.6 × 10 6 t )
with E in volts per meter and t in seconds. At t = 0 , the field is upward. The plate area is 3.6 × 10 2 m 2 . For t > 0 , what is the magnitude of the displacement current between the plates?

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