VDD = 5 V, Vtn = 0.7 V, μnCox = 75 μA/V2, Vtp = −0.7 V, μpCox = 30 μA/

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VDD = 5 V, Vtn = 0.7 V, μnCox = 75 μA/V2, Vtp = −0.7 V, μpCox = 30 μA/V2, (W/L)1 = (W/L)3 = 3, (W/L)2 = (W/L)4 = 6, (W/L)5 = (W/L)6 = (W/L)7 = (W/L)8 is given for the circuit shown below. a) Give the truth table of the circuit shown below. Explain how the circuit works. b) Calculate the minimum value of (W/L) s so that the switching of the Q′ output from "1" to " 0 " occurs at 2.6 V. Explain your solution. c) Explain how you find the propagation delay tPHL.

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V_{D D} = 5 V, V_{t n} = 0.7 V, μ_{n} C_{o x} = 75 μ A / V^{2}, V_{t p} = - 0.7 V, μ_{p} C_{α x} = 30 μ A / V^{2}, (W / L)_{1} = (W / L)_{3} = 3

(W / L)_{2} = (W / L)_{4} = 6, (W / L)_{5} = (W / L)_{6} = (W / L)_{7} = (W / L)_{8}

is given for the circuit shown below. a) Give the truth table of the circuit shown below. Explain how the circuit works. b) Calculate the minimum value of