VN is 0 V. vcontrolP Switches from 5 V to 0 V and stays at 0 V till capacitor settles to final value. d) Initial voltage condition on capacitor CL is 0 V. VN is 5 V. VcontrolP switches from 5 V to 0 V and stays at 0 V till capacitor settles to final value. e) Initial voltage condition on capacitor CL is 0 V. VN is 3 V. VcontrolN switches from 0 V to 5 V and stays at 5 V till capacitor settles to final value.
![Consider a pseudo NMOS inverter shown below. Use the following equations for your calculations. Saturation region current-voltage equation: ID = 12 kp, n′p, nWL(VGS−VT0 p, n)2 Linear region current-voltage equation: ID = 12 kp, n′WL[2(VGS−VT0 p, n)VDS−VDS2] Transistor parameters: kp′ = μpcox = 55 uA/V2, kn′ = μncox = 100 uA/V2, VTN = 1 V, VTP = −1 V, WN = 12 u, LP = 1 u, LN = 1 u. Pseudo NMOS Inverter a) Find the value of WP if Vin = 5 V results in Vout = 0.25 V. b) Find the value of Vout if Vin switches from 5 V to 0 V. c) Find the value of the switching threshold voltage VM(Vin = Vout ). d) Derive an expression of the output capacitor in terms of CGS and CGD capacitors of the transistors.](https://www.doubtrix.com/uploads/editor/4102759034QhUimpEAoQ.png)
