What is the fall time for a minimum size CMOS inverter in which both W/L ratios are 2/1, assume a load capacitance of 0,8 pF and VDD = 2,5 V, (VTN = |VTP| = 0.6 V, Kn' = 100 μA/V2, kp′ = 40 μA/V2)? a. 3,16 ns b. 7,58 ns c. 3.79 ns d 2.25 ns e 4.75 ns

What is the fall time for a minimum size CMOS inverter in which both W/L ratios are 2/1, assume a load capacitance of 0,8 pF and VDD = 2,5 V, (VTN = |VTP| = 0.6 V, Kn' = 100 μA/V2, kp′ = 40 μA/V2)? a. 3,16 ns b. 7,58 ns c. 3.79 ns d 2.25 ns e 4.75 ns

Image text
What is the fall time for a minimum size CMOS inverter in which both W/L ratios are 2 / 1 , assume a load capacitance of 0 , 8 p F and V D D = 2 , 5 V , ( V T N = V T P ∣= 0.6 V , K n = 100 m M , k p = 40 μ A N 2 ) ? a. 3 , 16 n s b. 7 , 58 n s c. 3.79 ns d 2.25 ns e 475 ns

Detailed Answer