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What is the off current, loff, in nanoamps for an NMOS FET at 300∘K when it has Vgs = 0V ? Assume that this MOSFET has a steep retrograde body doping profile with a maximum depletion region thickness of Wdmax = 42 nm, and an effective oxide thickness, Toxe, of 32 angstroms. Use: W = 2.3 μm, L = 0.2 μm, Vt = 280 mV and kT/q = 26 mV at 300∘K. (Please note that you can enter small numbers in Moodle in exponential format. For example, 0.0021 can be entered as 2.1 e−3 ) Answer: The correct answer is: 0.179

What is the off current, loff, in nanoamps for an NMOS FET at 300∘K when it has Vgs = 0V ? Assume that this MOSFET has a steep retrograde body doping profile with a maximum depletion region thickness of Wdmax = 42 nm, and an effective oxide thickness, Toxe, of 32 angstroms. Use: W = 2.3 μm, L = 0.2 μm, Vt = 280 mV and kT/q = 26 mV at 300∘K. (Please note that you can enter small numbers in Moodle in exponential format. For example, 0.0021 can be entered as 2.1 e−3 ) Answer: The correct answer is: 0.179

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What is the off current, loff, in nanoamps for an NMOS FET at 300 ∘ K when it has Vgs = OV ? Assume that this MOSFET has a steep retrograde body doping profile with a maximum depletion region thickness of Wdmax = 42 n m , and an effective oxide thickness, Toxe, of 32 angstroms. Use: W = 2.3 μ m , L = 0.2 μ m , V t = 280 m V and k T / q = 26 m V at 300 ∘ K . (Please note that you can enter small numbers in Moodle in exponential format. For example, 0.0021 can be entered as 2.1 e − 3 )
Answer: ◻ The correct answer is: 0.179

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