A 25-foot ladder is leaning against a house (see figure). If the base

Question

Notify Me Bookmark

A 25-foot ladder is leaning against a house (see figure). If the base of the ladder is pulled away from the house at a rate of 2 feet per second, the top will move down the wall at a rate of r = 2x 625−x2 ft/sec, where x is the distance between the base of the ladder and the house. Find the rate r when x is 24 feet. r = 48/7 ft/sec r = 7/24 ft/sec r = 48/5 ft/sec r = 7/48 ft/sec r = 24/7 ft/sec

Image text

A 25 -foot ladder is leaning against a house (see figure). If the base of the ladder is pulled away from the house at a rate of 2 feet per second, the top will move down the wall at a rate of $r = \frac{2 x}{\sqrt{625 - x^{2}}} f t / s e c$ , where $x$ is the distance between the base of the ladder and the house. Find the rate $r$ when $x$ is 24 feet. $r = \frac{48}{7} f t / s e c$ $r = \frac{7}{24} f t / s e c$ $r = \frac{48}{5} f t / s e c$ $r = \frac{7}{48} f t / s e c$ $r = \frac{24}{7} f t / s e c$