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A jug of juice is taken out of the refrigerator at 11:00 and is left on the kitchen counter. The temperature of the refrigerator is 5∘C and that of the kitchen is 22∘C. One hour later, the jug of juice reaches a temperature of 11∘C. Let T(t) represent the temperature of the jug t hours after 11:00. (i) Supposing that the temperature of the jug follows Newton's Law of Cooling, determine the exact formula for T(t), by finding and solving the corresponding differential equation. T(t) = Q2 (ii) What is the temperature of the jug of juice at 13:00? Give the answer with a precision of one decimal place. Answer: Number ∘C

A jug of juice is taken out of the refrigerator at 11:00 and is left on the kitchen counter. The temperature of the refrigerator is 5∘C and that of the kitchen is 22∘C. One hour later, the jug of juice reaches a temperature of 11∘C. Let T(t) represent the temperature of the jug t hours after 11:00. (i) Supposing that the temperature of the jug follows Newton's Law of Cooling, determine the exact formula for T(t), by finding and solving the corresponding differential equation. T(t) = Q2 (ii) What is the temperature of the jug of juice at 13:00? Give the answer with a precision of one decimal place. Answer: Number ∘C

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A jug of juice is taken out of the refrigerator at 11 : 00 and is left on the kitchen counter. The temperature of the refrigerator is 5 ∘ C and that of the kitchen is 22 ∘ C . One hour later, the jug of juice reaches a temperature of 11 ∘ C . Let T ( t ) represent the temperature of the jug t hours after 11:00. (i) Supposing that the temperature of the jug follows Newton's Law of Cooling, determine the exact formula for T ( t ) , by finding and solving the corresponding differential equation.
T ( t ) =
◻ Q 2 (ii) What is the temperature of the jug of juice at 13:00? Give the answer with a precision of one decimal place.
Answer: ◻ Number ∘ C

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