A manufacturer of light bulbs wants to produce bulbs that last about 5

Question

Notify Me Bookmark

A manufacturer of light bulbs wants to produce bulbs that last about 500 hours but, of course, some bulbs burn out faster than others. Let F(t) be the fraction of the company's bulbs that burn out before t hours. F(t) lies between 0 and 1. Let r(t) = F′(t). What is the value of ∫0∞r(t)dt ? divergent ∫0∞r(t)dt = 1 ∫0∞r(t)dt = 2 ∫0∞r(t)dt = 0 ∫0∞r(t)dt = 500

$A manufacturer of light bulbs wants to produce bulbs that last about 500 hours but, of course, some bulbs burn out faster than others. Let F(t) be the fraction of the company's bulbs that burn out before t hours. F(t) lies between 0 and 1. Let r(t) = F′(t). What is the value of ∫0∞r(t)dt ? divergent ∫0∞r(t)dt = 1 ∫0∞r(t)dt = 2 ∫0∞r(t)dt = 0 ∫0∞r(t)dt = 500$

Image text

A manufacturer of light bulbs wants to produce bulbs that last about 500 hours but, of course, some bulbs burn out faster than others. Let

F (t)

be the fraction of the company's bulbs that burn out before

t

hours.

F (t)

lies between 0 and 1.

Let

r (t) = F^{'} (t)

. What is the value of

\int_{0}^{\infty} r (t) d t

? divergent

\int_{0}^{\infty} r (t) d t = 1

\int_{0}^{\infty} r (t) d t = 2

\int_{0}^{\infty} r (t) d t = 0

\int_{0}^{\infty} r (t) d t = 500

Detailed Answer

Ask Your Doubt Rate This Answer Request Video Solution

Previous question

Next question

Submit Questions

Similar/Related Questions

$Assume that two waves of light in air, of wavelength 480. nm, are initially π rad out of phase. One travels through a glass layer of index of refraction n1 = 1.45 and thickness L. The other travels through an equally thick plastic layer of index of refraction n2 = 1.65. What is the smallest value of L so that the waves end up exactly in phase once they pass through the two media? 1.20 × 103 nm 300 nm 480 nm 1.80 × 103 nm 960 nm$

Solution

Solution

Solution