An object is thrown vertically upward from the surface of a celestial body at a velocity of 24 meters per second. Its distance from the surface at t seconds is given by s(t) = −0.4t2 + 24t. a. How fast is the object moving 2 seconds after being thrown? b. How long after the object is thrown does it reach its maximum height? c. How high will the object go? a. The object's velocity after 2 seconds is m/sec. (Round to the nearest tenth as needed.) b. It takes the object sec to reach its maximum height. (Round to the nearest tenth as needed.) c. The object reaches a maximum height of m. (Round to the nearest tenth as needed.)
