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Consider the Alternating Series S = ∑ n = 1 ∞ (−1) n n 2 Using the Alternating Series Remainder Theorem, find the smallest value of N so that the partial sum SN has error |S − SN| < 0.00025 = 1/4000 (a) N = 323 (b) N = 2 (c) N = 32 (d) N = 63 (e) N = 171

Consider the Alternating Series S = ∑ n = 1 ∞ (−1) n n 2 Using the Alternating Series Remainder Theorem, find the smallest value of N so that the partial sum SN has error |S − SN| < 0.00025 = 1/4000 (a) N = 323 (b) N = 2 (c) N = 32 (d) N = 63 (e) N = 171

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Consider the Alternating Series S = ∑ n = 1 ∞ ( − 1 ) n n 2
Using the Alternating Series Remainder Theorem, find the smallest value of N so that the partial sum S N has error | S − S N | < 0.00025 = 1 4000
(a) N = 323
(b) N = 2
(c) N = 32
(d) N = 63
(e) N = 171

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