Determine whether the argument form is valid and explain how the truth table supports your answer. The argument is valid because all rows that have true premises have false conclusions. The argument is valid because all rows that have true premises have true conclusions. The argument is valid because all rows that have false premises have false conclusions. The argument is invalid because there exists a row that has true premises and a false conclusion. The argument is invalid because there exists a row that has false premises and a true conclusion.
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Determine whether the argument form is valid and explain how the truth table supports your answer. The argument is valid because all rows that have true premises have false conclusions. The argument is valid because all rows that have true premises have true conclusions. The argument is valid because all rows that have false premises have false conclusions. The argument is invalid because there exists a row that has true premises and a false conclusion. The argument is invalid because there exists a row that has false premises and a true conclusion.
![7. (Poisson Distribution.) Let’s calculate the probability of having n particles in a subvolume V, for a box with total volume KV and a total number of particles T = KN0. (a) Find the exact formula for this probability: n particles in V, with total of T particles in KV. [Hint] What is the probability that the first n particles fall in the subvolume V, and the remainder T - n fall outside the subvolume (K - 1)V? How many ways are there to pick n particles from T total particles? (b) As K → ∞, show that the probability that n particles fall in the subvolume V has the Poisson distribution. What is the mean of this distribution? [Hint] You’ll need to use the fact that e -a = (e -1/K)Ka → (1 - 1/K) Ka as K → ∞, and the fact that n ≪ T. Here don’t assume that n is large: the Poisson distribution is valid even if there are only a few events.](https://www.doubtrix.com/uploads/editor/1022539071bGWWCRzJIA.png)
