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Does the series ∑n = 1∞(−1)nn4 n6+4 converge absolutely, converge conditionally, or diverge? A. The series converges absolutely because the limit used in the nth-Term Test is B. The series diverges because the limit used in the Ratio Test is not less than or equal to 1. C. The series diverges because the limit used in the nth-Term Test is not zero. D. The series converges absolutely per the Comparison Test with ∑n = 1∞1 n2. E. The series converges conditionally per the Alternating Series Test and because the limit used in the Root Test is F. The series converges conditionally per the Alternating Series Test and the Comparison Test with ∑n = 1∞1 n2.

Does the series ∑n = 1∞(−1)nn4 n6+4 converge absolutely, converge conditionally, or diverge? A. The series converges absolutely because the limit used in the nth-Term Test is B. The series diverges because the limit used in the Ratio Test is not less than or equal to 1. C. The series diverges because the limit used in the nth-Term Test is not zero. D. The series converges absolutely per the Comparison Test with ∑n = 1∞1 n2. E. The series converges conditionally per the Alternating Series Test and because the limit used in the Root Test is F. The series converges conditionally per the Alternating Series Test and the Comparison Test with ∑n = 1∞1 n2.

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Does the series ∑ n = 1 ∞ ( − 1 ) n n 4 n 6 + 4 converge absolutely, converge conditionally, or diverge? A. The series converges absolutely because the limit used in the nth-Term Test is ◻ B. The series diverges because the limit used in the Ratio Test is not less than or equal to 1. C. The series diverges because the limit used in the nth-Term Test is not zero. D. The series converges absolutely per the Comparison Test with ∑ n = 1 ∞ 1 n 2 . E. The series converges conditionally per the Alternating Series Test and because the limit used in the Root Test is ◻ F. The series converges conditionally per the Alternating Series Test and the Comparison Test with ∑ n = 1 ∞ 1 n 2 .

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