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Find an equation of the tangent line to the graph of the function given below at the given point. 6x2 − 4xy + 4y2 − 14 = 0, (1,2) (The coefficients below are given to two decimal places.) y = 0.33x+2.33 y = 2.67x−0.67 y = −0.33x+2.33 y = −0.33x+0.67 y = 2.67x+0.67

Find an equation of the tangent line to the graph of the function given below at the given point. 6x2 − 4xy + 4y2 − 14 = 0, (1,2) (The coefficients below are given to two decimal places.) y = 0.33x+2.33 y = 2.67x−0.67 y = −0.33x+2.33 y = −0.33x+0.67 y = 2.67x+0.67

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Find an equation of the tangent line to the graph of the function given below at the given point.
6 x 2 − 4 x y + 4 y 2 − 14 = 0 , ( 1 , 2 )
(The coefficients below are given to two decimal places.) y = 0.33 x + 2.33 y = 2.67 x − 0.67 y = − 0.33 x + 2.33 y = − 0.33 x + 0.67 y = 2.67 x + 0.67

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