Find the area of the surface generated by revolving the curve x = 12 cos(2t), y = 5+12 sin(2t) on 0 ≤ t ≤ π2 about the x-axis. The area of the surface generated by revolving the curve x = 12 cos(2t), y = 5+12 sin(2t) on 0 ≤ t ≤ π2 is square units. (Type an exact answer in terms of π. )