Find the area of the surface generated by revolving the curve x = 12 cos⁡(2t), y = 5+12 sin⁡(2t) on 0 ≤ t ≤ π2 about the x-axis. The area of the surface generated by revolving the curve x = 12 cos⁡(2t), y = 5+12 sin⁡(2t) on 0 ≤ t ≤ π2 is square units. (Type an exact answer in terms of π. )

Find the area of the surface generated by revolving the curve x = 12 cos⁡(2t), y = 5+12 sin⁡(2t) on 0 ≤ t ≤ π2 about the x-axis. The area of the surface generated by revolving the curve x = 12 cos⁡(2t), y = 5+12 sin⁡(2t) on 0 ≤ t ≤ π2 is square units. (Type an exact answer in terms of π. )

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Find the area of the surface generated by revolving the curve x = 1 2 cos ( 2 t ) , y = 5 + 1 2 sin ( 2 t ) on 0 t π 2 about the x -axis. The area of the surface generated by revolving the curve x = 1 2 cos ( 2 t ) , y = 5 + 1 2 sin ( 2 t ) on 0 t π 2 is square units. (Type an exact answer in terms of π .)

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