Find the volume of a solid of revolution formed by revolving the region bounded above by f(x) = x + 1 and below by the x-axis over the interval [0, 2] around the line y = −3. Answer exactly. units3
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Find the volume of a solid of revolution formed by revolving the region bounded above by and below by the -axis over the interval around the line . Answer exactly.
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![Find the volume of a solid of revolution formed by revolving the region bounded above by f(x) = x + 1 and below by the x-axis over the interval [0, 2] around the line y = −3. Answer exactly. units3](https://www.doubtrix.com/uploads/editor/6229722465BCidFFUKNb.jpg)
![Find the volume of a solid of revolution formed by revolving the region bounded above by f(x) = x + 1 and below by the x-axis over the interval [0, 3] around the line y = −2. Answer exactly. units 3](https://www.doubtrix.com/uploads/editor/0096777993tVixyfIVbF.jpg)
![R is the region bounded above by the graph of f(x) = 6x - 2x^2 and below by the x-axis over the interval [0, 3]. Find the volume of the solid of revolution formed by revolving R around the y-axis. Submit an exact answer in terms of π.](https://www.doubtrix.com/uploads/editor/3770108468ZPQTvWOXER.png)
![R is the region bounded above by the graph of f(x) = 2x^2/3 and below by the x-axis over the interval [0, 3]. Find the volume of the solid of revolution formed by revolving R around the y-axis. Submit an exact answer in terms of π.](https://www.doubtrix.com/uploads/editor/9809816686gWhwVbarxH.png)