Let f(x) = x - 3 over the interval [3, 5]. Find the surface area of the surface generated by revolving the graph of f(x) around the x-axis. Enter an exact answer.
![Let f(x) = x - 3 over the interval [3, 5]. Find the surface area of the surface generated by revolving the graph of f(x) around the x-axis. Enter an exact answer.](https://www.doubtrix.com/uploads/editor/1567475398iHkfcGlFcK.png)
For a nonnegative smooth function f(x) over the interval [a, b], use formula of the surface area of the surface of revolution created by revolving the graph of y = f(x) around the x-axis.
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Work With Experts to Reach at Correct Answers![Let f(x) = √3x over the interval [0, 1]. Find the surface area of the surface generated by revolving the graph of f(x) around the x-axis. Enter an exact answer.](https://www.doubtrix.com/uploads/editor/4817034447fiidPqqOBP.png)
![Let f(x) = 1/2 √3x over the interval [0, 3]. Find the surface area of the surface generated by revolving the graph of f(x) around the x-axis. Enter an exact answer.](https://www.doubtrix.com/uploads/editor/7897373093eFAaycTBzz.png)
![Set up an integral that represents the surface area of the surface generated by revolving the graph of f(x) = √6x - 2 around the x-axis over the interval [1, 3]. Do not evaluate the integral.](https://www.doubtrix.com/js/ckeditor/filemanager/connectors/php/editor/1701968209-Qmznxbksfholhz.png)