Set up and evaluate the integral that gives the volume of the solid fo

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Set up and evaluate the integral that gives the volume of the solid formed by revolving the region bounded by y = x9 and y = 512 in the first quadrant about the y-axis. V = π∫09 y29 dy = 18, 43211π V = π∫0512 y19 dy = 9, 21611π V = π∫09 y29 dy = 9, 21611π V = π∫0512 y29 dy = 1843211π V = π∫0512 y29 dy = 9, 21611π

Set up and evaluate the integral that gives the volume of the solid formed by revolving the region bounded by y = x9 and y = 512 in the first quadrant about the y-axis. V = π∫09 y29 dy = 18, 43211π V = π∫0512 y19 dy = 9, 21611π V = π∫09 y29 dy = 9, 21611π V = π∫0512 y29 dy = 1843211π V = π∫0512 y29 dy = 9, 21611π

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Set up and evaluate the integral that gives the volume of the solid formed by revolving the region bounded by

y = x^{9}

and

y = 512

in the first quadrant about the

y

-axis.

V = π \int_{0}^{9} y^{\frac{2}{9}} d y = \frac{18, 432}{11} π

V = π \int_{0}^{512} y^{\frac{1}{9}} d y = \frac{9, 216}{11} π

V = π \int_{0}^{9} y^{\frac{2}{9}} d y = \frac{9, 216}{11} π

V = π \int_{0}^{512} y^{\frac{2}{9}} d y = \frac{18432}{11} π

V = π \int_{0}^{512} y^{\frac{2}{9}} d y = \frac{9, 216}{11} π

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