The resistance R of a certain type of resistor is R = 0.003T4 − 5T + 1

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The resistance R of a certain type of resistor is R = 0.003T4 − 5T + 100 where R is measured in ohms and the temperature T is measured in degrees Celsius. Use a computer algebra system to find dR dT dR dT = 0.003T3−5 2 0.003T4−5T+100 dR dT = 0.012T4−5T 2 0.003T4−5T+100 dR dT = 0.012T3−5 2 0.003T4−5T+100 dR dT = 3T3 500 0.003T4−5T+100 dR dT = 0.003T3−5 2 0.003T4−5

The resistance R of a certain type of resistor is R = 0.003T4 − 5T + 100 where R is measured in ohms and the temperature T is measured in degrees Celsius. Use a computer algebra system to find dR dT dR dT = 0.003T3−5 2 0.003T4−5T+100 dR dT = 0.012T4−5T 2 0.003T4−5T+100 dR dT = 0.012T3−5 2 0.003T4−5T+100 dR dT = 3T3 500 0.003T4−5T+100 dR dT = 0.003T3−5 2 0.003T4−5

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The resistance

R

of a certain type of resistor is

R = \sqrt{0.003 T^{4} - 5 T + 100}

where

R

is measured in ohms and the temperature

T

is measured in degrees Celsius. Use a computer algebra system to find

\frac{d R}{d T}

\frac{d R}{d T} = \frac{\sqrt{0.003 T^{3} - 5}}{2 \sqrt{0.003 T^{4} - 5 T + 100}}

\frac{d R}{d T} = \frac{0.012 T^{4} - 5 T}{2 \sqrt{0.003 T^{4} - 5 T + 100}}

\frac{d R}{d T} = \frac{0.012 T^{3} - 5}{2 \sqrt{0.003 T^{4} - 5 T + 100}}

\frac{d R}{d T} = \frac{3 T^{3}}{500 \sqrt{0.003 T^{4} - 5 T + 100}}

\frac{d R}{d T} = \frac{\sqrt{0.003 T^{3} - 5}}{2 \sqrt{0.003 T^{4} - 5}}

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