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Use l'Hôpital's rule to find the limit. limx→0 6x2/cos x - 1 What must be done to put the given expression in a form to which l'Hôpital's rule can be directly applied? A. Nothing, the given expression already has the indeterminate form 0/0 . B. Nothing, the given expression already has the indeterminate form ∞/∞ . C. Nothing, the given expression already has the indeterminate form 0⋅∞. D. The expression must be rewritten as limx→06x2 (sec x - 1). Find the limit. limx→0 6x2/cos x-1 = (Type an exact answer.)

Use l'Hôpital's rule to find the limit. limx→0 6x2/cos x - 1 What must be done to put the given expression in a form to which l'Hôpital's rule can be directly applied? A. Nothing, the given expression already has the indeterminate form 0/0 . B. Nothing, the given expression already has the indeterminate form ∞/∞ . C. Nothing, the given expression already has the indeterminate form 0⋅∞. D. The expression must be rewritten as limx→06x2 (sec x - 1). Find the limit. limx→0 6x2/cos x-1 = (Type an exact answer.)

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Use l'Hôpital's rule to find the limit. limx→0 6x2/cos x - 1 What must be done to put the given expression in a form to which l'Hôpital's rule can be directly applied? A. Nothing, the given expression already has the indeterminate form 0/0 . B. Nothing, the given expression already has the indeterminate form ∞/∞ . C. Nothing, the given expression already has the indeterminate form 0⋅∞. D. The expression must be rewritten as limx→06x2 (sec x - 1). Find the limit. limx→0 6x2/cos x-1 = (Type an exact answer.)

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