Question

Notify Me Bookmark

0.200 coulombs of charge pass a point in a wire in 5.00 seconds. The current in Amps is: A

0.200 coulombs of charge pass a point in a wire in 5.00 seconds. The current in Amps is: A

Image text
0.200 coulombs of charge pass a point in a wire in 5.00 seconds. The current in Amps is: ◻ A

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

How many electrons flow through a point in a wire in 3.00 s if there is a constant current of I = 4.00 A? Negative charge of an electron = 1.609 × 10 −19 C 8.0 × 10^19 7.5 × 10^19 8.5 × 10^19 9.0 × 10^19

Solution
0 0

The direction of that field can be found using a right-hand rule. Place the thumb in the direction of the current and wrap the fingers around the wire in the direction of the magnetic field, as shown in the figure below. (i) If the current in the above figure is reversed and now points downward, what is the direction of the magnetic field? clockwise counterclockwise The equation for the strength of the magnetic field due to the current I in a long, straight wire was experimentally found to be the following. B = μ0 I2πr The proportionality constant μ0 is called the permeability of free space. μ0≡4π×10−7 T⋅m/A Calculate the magnetic field (in T) at a distance 6.0 cm away from a wire that carries a current of 0.50 A . T
Solution
0 0

The circuit shown in the figure is used to make a magnetic balance to weigh objects. The mass m to be measured is hung from the center of the bar, that is in a uniform magnetic field of 1.50 T, directed into the plane of the figure. The battery voltage can be adjusted to vary the current in the circuit. The horizontal bar is 60.0 cm long and is made of extremely light-weight material. It is connected to the battery by thin vertical wires that can support no appreciable tension; all the weight of the suspended mass m is supported by the magnetic force on the bar. A resistor with R = 5.00 Ω is in series with the bar; the resistance of the rest of the circuit is much less than this. (Figure 1) Figure 1 of 1 Part A Which point, a or b, should be the positive terminal of the battery? a b Submit Request Answer Part B If the maximum terminal voltage of the battery is 175 V, what is the greatest mass m that this instrument can measure? Express your answer in kilograms. m = kg The circuit shown in the figure is used to make a magnetic balance to weigh objects. The mass m to be measured is hung from the center of the bar, that is in a uniform magnetic field of 1.50 T, directed into the plane of the figure. The battery voltage can be adjusted to vary the current in the circuit. The horizontal bar is 60.0 cm long and is made of extremely light-weight material. It is connected to the battery by thin vertical wires that can support no appreciable tension; all the weight of the suspended mass m is supported by the magnetic force on the bar. A resistor with R = 5.00 Ω is in series with the bar; the resistance of the rest of the circuit is much less than this. (Figure 1) Figure 1 of 1 Part A Which point, a or b, should be the positive terminal of the battery? a b Submit Request Answer Part B If the maximum terminal voltage of the battery is 175 V, what is the greatest mass m that this instrument can measure? Express your answer in kilograms. m = kg

Solution
0 0