Question

Notify Me Bookmark

A 2100-kg car drives with a speed of 18 m/s on a flat road around a curve that has a radius of curvature of 83 m. The coefficient of static friction between the car and the road is 0.78. What is the magnitude of the force of static friction acting on the car? 1.6×104 N 2.1×104 N 8.2×103 N The car will slide as it goes around the curve because the static friction is not strong enough. 5.7×103 N

A 2100-kg car drives with a speed of 18 m/s on a flat road around a curve that has a radius of curvature of 83 m. The coefficient of static friction between the car and the road is 0.78. What is the magnitude of the force of static friction acting on the car? 1.6×104 N 2.1×104 N 8.2×103 N The car will slide as it goes around the curve because the static friction is not strong enough. 5.7×103 N

Image text
A 2100 − kg car drives with a speed of 18 m / s on a flat road around a curve that has a radius of curvature of 83 m . The coefficient of static friction between the car and the road is 0.78 . What is the magnitude of the force of static friction acting on the car? 1.6 × 10 4 N 2.1 × 10 4 N 8.2 × 10 3 N The car will slide as it goes around the curve because the static friction is not strong enough. 5.7 × 10 3 N

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

A radio controlled car, with a mass of 3.0 kg, travels counterclockwise around the curved path shown (viewed from above, gravity is directed into the paper). The radius of curvature of the path is 2.0 m. When at the top of the curve (shown) the speed of the car is 2 m/s and it is slowing down with aT = −2.1 m/s2. The car is not slipping. a. What is the frictional force vector that the ground is applying to the car at the point shown? (Express the force in terms of i and j unit vectors.) b. What is the force that the ground is applying to the car in the z-direction (out of the paper)? c. What is the magnitude of the total force that the ground is applying to the car? d. What is the minimum static coefficient of friction such that the car would not slip at the time shown?
Solution
0 0

Engineering a highway curve. If a car goes through a curve too fast, the car tends to slide out of the curve. For a banked curve with friction, a frictional force acts on a fast car to oppose the tendency to slide out of the curve; the force is directed down the bank (in the direction water would drain). Consider a circular curve of radius R = 220 m and bank angle θ, where the coefficient of static friction between tires and pavement is μs. A car (without negative lift) is driven around the curve as shown in the figure below. Find an expression for the car speed vmax that puts the car on the verge of sliding out, in terms of R, θ, and μs. Evaluate vmax for a bank angle of θ = 11∘ and for (a) μs = 0.77 (dry pavement) and (b) μs = 0.047 (wet or icy pavement). (Now you can see why accidents occur in highway curves when icy conditions are not obvious to drivers, who tend to drive at normal speeds. ) (a) Number Units (b) Number Units
Solution
0 0

Engineering a highway curve. If a car goes through a curve too fast, the car tends to slide out of the curve. For a banked curve with friction, a frictional force acts on a fast car to oppose the tendency to slide out of the curve; the force is directed down the bank (in the direction water would drain). Consider a circular curve of radius R = 220 m and bank angle θ, where the coefficient of static friction between tires and pavement is μs. A car (without negative lift) is driven around the curve as shown in the figure below. Find an expression for the car speed vmax that puts the car on the verge of sliding out, in terms of R, θ, and μs. Evaluate vmax for a bank angle of θ = 11∘ and for (a) μs = 0.77 (dry pavement) and (b) μs = 0.047 (wet or icy pavement). (Now you can see why accidents occur in highway curves when icy conditions are not obvious to drivers, who tend to drive at normal speeds.)
Solution
0 0