Question

Notify Me Bookmark

A 60-watt light bulb carries a current of 0.5 ampere. The total charge passing through it in one hour is: 3600 C 3000 C 2400 C 1800 C 120 C

A 60-watt light bulb carries a current of 0.5 ampere. The total charge passing through it in one hour is: 3600 C 3000 C 2400 C 1800 C 120 C

Image text
A 60-watt light bulb carries a current of 0.5 ampere. The total charge passing through it in one hour is: 3600 C 3000 C 2400 C 1800 C 120 C

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

Exercise 30.19 A solenoid 20.0 cm long and with a cross-sectional area of 0.570 cm2 contains 460 turns of wire and carries a current of 70.0 A. Part A Calculate the magnetic field in the solenoid. Part B Calculate the energy density in the magnetic field if the solenoid is filled with air. Part C Calculate the total energy contained in the coil's magnetic field (assume the field is uniform). Part D Calculate the inductance of the solenoid. L = HExercise 30.19 A solenoid 20.0 cm long and with a cross-sectional area of 0.570 cm2 contains 460 turns of wire and carries a current of 70.0 A. Part A Calculate the magnetic field in the solenoid. Part B Calculate the energy density in the magnetic field if the solenoid is filled with air. Part C Calculate the total energy contained in the coil's magnetic field (assume the field is uniform). Part D Calculate the inductance of the solenoid. L = H
Solution
0 0

A rectangular wire frame with 4 m×10 m size carries a current of I = 5 A and is placed as shown in the figure where the angle is θ = 37∘. There is a uniform external magnetic field B→ = 4 i^ T. (a) What is the net force acting on the wire frame? Coding note: i^:ihat, j^:jhat, k^:khat, F→ = N (b) What is the net torque acting on the wire frame? τ→ = Nm (c) Suppose that the wire frame is initially at rest. It then starts to rotate only under the effect of the external magnetic field. At the time when the frame is passing through its minimum potential energy configuration . . . what is the final kinetic energy of the frame? Kf = J
Solution
0 0

Consider a DRAM cell that uses an internal capacitor of 20 fF; it is charged to 3.3 V when storing a ' 1 '. In this problem, ignore body effect. (A real transistor like the access transistor here, or pass transistors in switch logic, can turn off before you want it to because of body effect; this one stays on until the 20 fF capacitor is fully charged. ) (6-points) (a) When writing a ' 1 ', how long does it take for the voltage on the capacitor to rise to 95% of its final value? Assume that when it is on, the access transistor in the cell has an average resistance of 6 kΩ; assume that the inverter driving the bit line has an average pull-up resistance of 1 kΩ. Ignore the resistance and capacitance of the bit line itself. (In a real memory, wire parasitics play a big role!)? (b) Suppose that when reading, the bit line is first charged to 3.3 V. The bit line is a large piece of metal, and has a total capacitance of 500 fF. How far does the bit line drop in voltage if a ' 0 ' is read? (Hint: In circuits, you learned that charge on capacitors in parallel redistributes until the voltage is equal; assume enough time is given for the bit line to drop as far as it ever will. )? (c) Suppose that the leakage current from the cell, due to the reverse-biased diode and subthreshold MOSFET currents, is no more than 2 pA. If a signal loss on the capacitor of 0.5 V can be tolerated, how often must the DRAM cell be refreshed to ensure that no data is lost?

Solution
0 0