Question

Notify Me Bookmark

A ball is thrown straight up from a rooftop 192 feet high. The formula below describes the ball's height above the ground, h, in feet, t seconds after it was thrown. The ball misses the rooftop on its way down and eventually strikes the ground. How long will it take for the ball to hit the ground? Use this information to provide tick marks with appropriate numbers along the horizontal axis in the figure shown. h = −16t2 + 16t + 192 The ball hits the ground after seconds. Each tick represents second(s).

A ball is thrown straight up from a rooftop 192 feet high. The formula below describes the ball's height above the ground, h, in feet, t seconds after it was thrown. The ball misses the rooftop on its way down and eventually strikes the ground. How long will it take for the ball to hit the ground? Use this information to provide tick marks with appropriate numbers along the horizontal axis in the figure shown. h = −16t2 + 16t + 192 The ball hits the ground after seconds. Each tick represents second(s).

Image text
A ball is thrown straight up from a rooftop 192 feet high. The formula below describes the ball's height above the ground, h , in feet, t seconds after it was thrown. The ball misses the rooftop on its way down and eventually strikes the ground. How long will it take for the ball to hit the ground? Use this information to provide tick marks with appropriate numbers along the horizontal axis in the figure shown.
h = − 16 t 2 + 16 t + 192
The ball hits the ground after ◻ seconds.
Each tick represents ◻ second(s).

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

Bob has just finished climbing a sheer cliff above a level beach and wants to figure out how high he climbed. All he has to use is a baseball, a stopwatch, and a friend on the ground below with a long measuring tape. Bob is a pitcher, and knows that the fastest he can throw the ball is about v0 = 31.7 m/s. Bob starts the stopwatch as he throws the ball, with no way to measure the ball's initial trajectory, and watches carefully. The ball rises and then falls, and after t1 = 0.710 s the ball is once again level with Bob. Bob cannot see well enough to time when the ball hits the ground. Bob's friend then measures that the ball hit the ground x = 129 m from the base of the cliff. How high h above the beach was the ball when it was thrown? h =
Solution
0 0

In the figure, a ball is thrown leftward from the left edge of the roof, at height h above the ground. The ball hits the ground 1.80 s later, at distance d = 22.0 m from the building and at angle θ = 60.0∘ with the horizontal. (a) Find h. (Hint: One way is to reverse the motion, as if on videotape.) What are the (b) magnitude and (c) angle relative to the horizontal of the velocity at which the ball is thrown (positive angle for above horizontal, negative for below)? (a) Number Units m (b) Number Units (c) Number Units
Solution
0 0

In the figure, a ball is thrown leftward from the left edge of the roof, at height h above the ground. The ball hits the ground 2.40 s later, at distance d = 22.0 m from the building and at angle θ = 64.0∘ with the horizontal. (a) Find h. (Hint: One way is to reverse the motion, as if on videotape.) What are the (b) magnitude and (c) angle relative to the horizontal of the velocity at which the ball is thrown (positive angle for above horizontal, negative for below)?
Solution
0 0