A block of mass m1 = 8 kg that is free to move along a horizontal frictionless table, is connected by a string that wraps over a frictionless pulley to a second block of mass m2 = 3 kg which is hanging above the ground. The table is accelerating upward with constant acceleration a0 = 2 m/s2. a. At which acceleration does block m2 falls relative to the table (that is, relative to an observer that is standing on the table)? One possible correct answer is: 3.2181818181818 Now the table is accelerated to the right with acceleration a0, as seen in the figure: b. What will be the downward acceleration of block m2 relative to the table in this case? One possible correct answer is: 1.2181818181818

A block of mass m1 = 8 kg that is free to move along a horizontal frictionless table, is connected by a string that wraps over a frictionless pulley to a second block of mass m2 = 3 kg which is hanging above the ground. The table is accelerating upward with constant acceleration a0 = 2 m/s2. a. At which acceleration does block m2 falls relative to the table (that is, relative to an observer that is standing on the table)? One possible correct answer is: 3.2181818181818 Now the table is accelerated to the right with acceleration a0, as seen in the figure: b. What will be the downward acceleration of block m2 relative to the table in this case? One possible correct answer is: 1.2181818181818

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A block of mass m 1 = 8 k g that is free to move along a horizontal frictionless table, is connected by a string that wraps over a frictionless pulley to a second block of mass m 2 = 3 k g which is hanging above the ground. The table is accelerating upward with constant acceleration a 0 = 2 m / s 2 . a. At which acceleration does block m 2 falls relative to the table (that is, relative to an observer that is standing on the table)? One possible correct answer is: 3.2181818181818 Now the table is accelerated to the right with acceleration a 0 , as seen in the figure: b. What will be the downward acceleration of block m 2 relative to the table in this case? One possible correct answer is: 1.2181818181818

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