Question

Notify Me Bookmark

A buoy floating in the ocean is bobbing in simple harmonic motion with period 6 seconds and amplitude 5 ft. Its displacement d from sea level at time t = 0 seconds is 0 ft, and initially it moves upward. (Note that upward is the positive direction.) Give the equation modeling the displacement d as a function of time t. d =

A buoy floating in the ocean is bobbing in simple harmonic motion with period 6 seconds and amplitude 5 ft. Its displacement d from sea level at time t = 0 seconds is 0 ft, and initially it moves upward. (Note that upward is the positive direction.) Give the equation modeling the displacement d as a function of time t. d =

Image text
A buoy floating in the ocean is bobbing in simple harmonic motion with period 6 seconds and amplitude 5 f t . Its displacement d from sea level at time t = 0 seconds is 0 f t , and initially it moves upward. (Note that upward is the positive direction.)
Give the equation modeling the displacement d as a function of time t .
d =
◻ π sin ⁡ ◻ cos ⁡ ◻

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

An object oscillates with simple harmonic motion along with x axis. Its displacement from the origin varies with time according to the equation x = (4.00 m)cos⁡(πt + π/4) Where t is in seconds and the angles in the parentheses are in radians. (a) Determine the amplitude, frequency and period of the motion. (b) Calculate the velocity and acceleration of the object at time t. (c) Using the results in part(b), determine the position, velocity and acceleration of the object at t = 1.0 s (d) Determine the maximum speed and acceleration of the object.
Solution
0 0

Problem 4. A particle of mass m is attached to two nearby walls by springs, each of which has spring constant k, as in the figure below. When the particle is situated at the midpoint between the two walls, both springs are un-stretched. The mass is now pulled to the right by an amount A, and then at time t = 0 is released from rest (i. e., with no initial velocity). Ignore gravity, and ignore any motion in the transverse (i. e., y ) direction. (20 points total) (a) By applying Newton's laws of motion, find the differential equation that governs the subsequent motion of the particle. (10 points) (b) What is x(t) for this particle? What is the frequency of oscillation of this particle, ω, as a function of k and m? (5 points) (c) What is the period of oscillation, T? (5 points)

Solution
0 0

A buoy oscillates in simple harmonic motion as waves go past. At a given time it is noted that the buoy moves a total of 4.4 feet from its low point to its high point, and that it returns to its high point every 14 seconds. Which equation best describes the motion of the buoy if at t = 0 it is at its high point? d = 115 cos⁡πt7 d = 4.4 cos⁡7πtd = 4.4 cos⁡14πtd = 4.4 cos⁡πt7 d = 115 cos⁡14πt d = 4.4 cos⁡πt14 d = 115 cos⁡πt14 d = 115 cos⁡7πtA buoy oscillates in simple harmonic motion as waves go past. At a given time it is noted that the buoy moves a total of 4.4 feet from its low point to its high point, and that it returns to its high point every 14 seconds. Which equation best describes the motion of the buoy if at t = 0 it is at its high point? d = 115 cos⁡πt7 d = 4.4 cos⁡7πtd = 4.4 cos⁡14πtd = 4.4 cos⁡πt7 d = 115 cos⁡14πt d = 4.4 cos⁡πt14 d = 115 cos⁡πt14 d = 115 cos⁡7πt
Solution
0 0