Question

Notify Me Bookmark

A cannon is fired with an initial velocity of 120 m/s at an angle of 25° above a level field. The cannonball strikes the tallest tower of the castle, 3.4 s after it is fired. Δx At approximately what height above the ground does the cannonball strike the tower? NOTE: this diagram is NOT to scale! 50.7 m 131 m 116 m 343 m 191 m

A cannon is fired with an initial velocity of 120 m/s at an angle of 25° above a level field. The cannonball strikes the tallest tower of the castle, 3.4 s after it is fired. Δx At approximately what height above the ground does the cannonball strike the tower? NOTE: this diagram is NOT to scale! 50.7 m 131 m 116 m 343 m 191 m

Image text
A cannon is fired with an initial velocity of 120 m / s at an angle of 25 0 above a level field. The cannonball strikes the tallest tower of the castle, 3.4 s after it is fired. Δ x
At approximately what height above the ground does the cannonball strike the tower?
NOTE: this diagram is NOT to scale! 50.7 m 131 m 116 m 343 m 191 m

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

A baseball is thrown from the roof of h = 23.4-m-tall building with an initial velocity of magnitude 11.3 m/s and directed at an angle of 53.1∘ above the horizontal. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Energy in projectile motion. Part A What is the speed of the ball just before it strikes the ground? Use energy methods and ignore air resistance. Express your answer in meters per second. Part B What is the answer for part (A) if the initial velocity is at an angle of 53.1∘ below the horizontal Express your answer in meters per second. v2 = m/s Submit Request Answer Part C If the effects of air resistance are included, will part (A) or (B) give the higher speed? The part (A) will give the higher speed. The part (B) will give the higher speed. A baseball is thrown from the roof of h = 23.4-m-tall building with an initial velocity of magnitude 11.3 m/s and directed at an angle of 53.1∘ above the horizontal. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Energy in projectile motion. Part A What is the speed of the ball just before it strikes the ground? Use energy methods and ignore air resistance. Express your answer in meters per second. Part B What is the answer for part (A) if the initial velocity is at an angle of 53.1∘ below the horizontal Express your answer in meters per second. v2 = m/s Submit Request Answer Part C If the effects of air resistance are included, will part (A) or (B) give the higher speed? The part (A) will give the higher speed. The part (B) will give the higher speed.

Solution
0 0

A projectile is fired from the edge of a cliff as shown in the figure at an angle of 30∘ above the horizontal. The cliff is 20 m high. The initial velocity is 13.4 m/s. The projectile reaches maximum height at point P and then falls and strikes the ground at point Q. How far from the base of the cliff does the projectile land (in m)? Neglect air resistance and use g = 9.81m s2 as the magnitude of the acceleration due to gravity.
Solution
0 0

A mball = 0.5 kg cannonball and is shot with an initial velocity of vA at an angle θ1. The cannonball bounces off the ground at point B. The coefficient of restitution between the ball and ground is e = 0.15. Ignore air resistance. Hint: Assume the ground is so large that it will not move. Values for the figure are given in the following table. Note the figure may not be to scale. Variable Value vA60 msd13 mθ124 degrees For all velocities, include negatives for direction if appropriate. a. Determine the y-component of the velocity of the cannonball right before it hits the ground, (VBy)1 b. Determine the y-component of the velocity of the cannonball right after it hits the ground, (VBy)2. c. Determine the max height the cannonball reaches after it hits the ground, h. Round your final answers to 3 significant digits/figures. (VBy)1 = m s (VBy)2 = m s h = m

Solution
0 0