Question

Notify Me Bookmark

A certain capacitor has a capacitance of 6 μF. While it is charged to 6 μC and isolated, the plates are pulled apart so its capacitance becomes 3 μF. The work done by the pulling agent is about 3×10−6 J 10×10−6 J 0 J 6×10−6 J 9×10−6 J

A certain capacitor has a capacitance of 6 μF. While it is charged to 6 μC and isolated, the plates are pulled apart so its capacitance becomes 3 μF. The work done by the pulling agent is about 3×10−6 J 10×10−6 J 0 J 6×10−6 J 9×10−6 J

Image text
A certain capacitor has a capacitance of 6 μ F . While it is charged to 6 μ C and isolated, the plates are pulled apart so its capacitance becomes 3 μ F . The work done by the pulling agent is about 3 × 10 − 6 J 10 × 10 − 6 J 0 J 6 × 10 − 6 J 9 × 10 − 6 J

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

A certain capacitor has a capacitance of 5 uF. While it is charged to 5 uC and isolated, the plates are pulled apart so its capacitance becomes 2 uF. The work done by the pulling agent is about
Solution
1 0

A certain capacitor has a capacitance of 5.0 μF. After it is charged to 5.0 μC and isolated, the plates are brought closer together so its capacitance becomes 10 μF. The work done is about 8.3×10−7 J 1.3×10−6 J 0 J −8.3×10−7 J −1.3×10−6 J
Solution
0 0

A certain capacitor has a capacitance of 5.0 μF. After it is charged to 5 μC and isolated, the plates are brought closer together so its capacitance becomes 10 μF. The work done by the agent is about: 0 J 1.25×10−6 J −1.25×10−6 J 8.3×10−7 J −8.3×10−7 J
Solution
0 0